4(y-3)=3[y+2(y+2)]

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Solution for 4(y-3)=3[y+2(y+2)] equation:


Simplifying
4(y + -3) = 3[y + 2(y + 2)]

Reorder the terms:
4(-3 + y) = 3[y + 2(y + 2)]
(-3 * 4 + y * 4) = 3[y + 2(y + 2)]
(-12 + 4y) = 3[y + 2(y + 2)]

Reorder the terms:
-12 + 4y = 3[y + 2(2 + y)]
-12 + 4y = 3[y + (2 * 2 + y * 2)]
-12 + 4y = 3[y + (4 + 2y)]

Reorder the terms:
-12 + 4y = 3[4 + y + 2y]

Combine like terms: y + 2y = 3y
-12 + 4y = 3[4 + 3y]
-12 + 4y = [4 * 3 + 3y * 3]
-12 + 4y = [12 + 9y]

Solving
-12 + 4y = 12 + 9y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-9y' to each side of the equation.
-12 + 4y + -9y = 12 + 9y + -9y

Combine like terms: 4y + -9y = -5y
-12 + -5y = 12 + 9y + -9y

Combine like terms: 9y + -9y = 0
-12 + -5y = 12 + 0
-12 + -5y = 12

Add '12' to each side of the equation.
-12 + 12 + -5y = 12 + 12

Combine like terms: -12 + 12 = 0
0 + -5y = 12 + 12
-5y = 12 + 12

Combine like terms: 12 + 12 = 24
-5y = 24

Divide each side by '-5'.
y = -4.8

Simplifying
y = -4.8

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